브라우저에서 간단하게 ajax test

var xhr = new XMLHttpRequest();

xhr.open("get", "http://localhost:3000/api/v1/oauth2/profile");
xhr.withCredentials = true;
xhr.send()


xhttp.open("POST", "/api/setScore",{data:temp2,score:9999});
xhttp.send()

브라우저에서 3rd part Lib load

var el = document.createElement('script');
el.src = "https://cdn.jsdelivr.net/lodash/4.17.4/lodash.min.js"; 
el.type = "text/javascript"; 
document.head.appendChild(el)

var xhr = new XMLHttpRequest(); xhr.open("post", "https://api-dev.gooroo.com/users");

xhr.setRequestHeader('X-API-KEY','1234') xhr.setRequestHeader('Access-Control-Allow-Origin', '*')

xhr.send()

var xhr = new XMLHttpRequest(); xhr.open("post", "http://192.168.2.241:3003/users");

xhr.setRequestHeader('X-API-KEY','1234') xhr.setRequestHeader('Access-Control-Allow-Origin', '*')

xhr.send()

xhr.withCredentials = true;